Ifsin=12/13,find the value of sin²_cos²/2sin2cosx1/tan²
sin²_cos²/2sin2cosx1/tan²
re-enter in proper form
e.g. sin = 12/13 is meaningless, "sin" is an operator and needs an operand
did you mean :
sinØ = 12/13 or sinx = 12/13 ??
that is like saying √ = 3 , or log = 1.3
and aside from that, what does 2sin2cos mean?
Try actually writing sin^2x or cosx or sin2x or something so we can tell the angles being used.
In any case, if sinx = 12/13 then cosx = 5/13, tanx = 12/5
Now just plug in those fractions for whatever expression you want to evaluate.
To find the value of sin²_cos²/2sin2cosx1/tan², we need to break down the expression step by step and calculate each part individually.
Let's start by calculating sin²_cos²:
1. Start with the given value of sin = 12/13.
sin² = (12/13)² = 144/169.
2. To calculate cos², we can use the identity cos² + sin² = 1.
cos² = 1 - sin² = 1 - 144/169 = 25/169.
Now, we have sin² = 144/169 and cos² = 25/169.
Next, let's find 2sin2cos:
1. Start with the given value of sin = 12/13.
sin2 = 2 * sin = 2 * (12/13) = 24/13.
2. Start with the given value of cos = √(1 - sin²) = √(1 - 144/169) = √(25/169) = 5/13.
cos2 = 2 * cos = 2 * (5/13) = 10/13.
Now, we have sin2 = 24/13 and cos2 = 10/13.
Lastly, let's find tan²:
1. Start with the given value of sin = 12/13.
cos = √(1 - sin²) = √(1 - 144/169) = √(25/169) = 5/13.
2. tan = sin / cos = (12/13) / (5/13) = (12/5).
3. tan² = (tan)² = (12/5)² = 144/25.
Now, we have tan² = 144/25.
Putting it all together, we have:
sin²_cos² / 2sin2cos * 1/tan² = (144/169) * (25/169) / (2 * (24/13) * (10/13)) * (1 / (144/25))
Simplifying this expression gives us the final answer.