Helen give her brother 1/3 of her money.spend 2/5 and save $28.00.
A. How much money helen had at first.
B.how much money did belen give her brother.
A)
Money she had = x
=> (1/3)x + (2/5)x + 28 = x
=> (11/15)x + 28 = x
=> 28 = (4/15)x
=> x = 28*(15/4)
= $105
B)
(1/3)*x = (1/3)*105 = ?
To solve this problem, we can break it down into a series of steps:
Step 1: Let's assume the amount of money Helen had at first is represented by 'x'.
Step 2: Helen gave her brother 1/3 of her money. To find out how much money she gave him, we need to calculate (1/3) * x.
Step 3: After giving her brother 1/3 of her money, Helen spent 2/5 of the remaining amount. So, we subtract (2/5) * x from the amount calculated in Step 2.
Step 4: We are told that after spending, Helen saved $28.00. We know that the amount left after spending is 28 dollars, so we can set up an equation: [(1/3) * x] - [(2/5) * x] = 28.
Step 5: Now we can solve the equation by combining like terms and isolating 'x'. We can start by finding a common denominator for 1/3 and 2/5, which is 15. Thus, the equation becomes: [(5/15) * x] - [(6/15) * x] = 28.
Step 6: Simplifying further, we have: [(5x - 6x) / 15] = 28. Now, combining like terms, we get: [-x / 15] = 28.
Step 7: To isolate 'x', we can multiply both sides of the equation by 15, giving us: -x = 28 * 15.
Step 8: Finally, we solve for 'x' by multiplying -1 on both sides of the equation: x = -28 * 15.
Step 9: Evaluating the final expression, we get: x = -420.
Therefore, Helen had -$420.00 at first. Please note that a negative value indicates a debt or a lack of money.