1.What are the mean,median,mode and range of the data set given the altitude of lakes in feet:-9,-36,-23,-8,-17,-52,-27,and-36?
2.Given the data 21,13,13,37,13,23,25,15
a.What is the outlier in the data?
b.what is the mean with the outlier?
c.what is the mean without the outlier?
3.Which frequency table represents the set of data below related how each student in a class traveled to school in the morning? And if there is anyone who knows the rest of the answers that would be helpful thank you. PLEASE HELP ME
1. To find the mean, median, mode, and range of the data set, first arrange the altitudes in ascending order: -52, -36, -36, -27, -23, -17, -9, -8.
Mean: Add all the altitudes and divide by the total number of data points:
(-52 + -36 + -36 + -27 + -23 + -17 + -9 + -8) / 8 = -208 / 8 = -26
Median: The median is the middle value when the data is arranged in ascending order. Since there are 8 data points (an even number), the median is the average of the two middle values (-27 and -23):
(-27 + -23) / 2 = -50 / 2 = -25
Mode: The mode is the value that appears most frequently in the data set. In this case, the mode is -36 because it appears twice.
Range: The range is the difference between the highest and lowest values in the data set:
-8 - (-52) = -8 + 52 = 44
So, the mean is -26, the median is -25, the mode is -36, and the range is 44.
2. Given the data 21, 13, 13, 37, 13, 23, 25, 15:
a. The outlier in the data is 37, as it is significantly higher than the rest of the data points.
b. To find the mean with the outlier, add all the data points and divide by the total number of data points:
(21 + 13 + 13 + 37 + 13 + 23 + 25 + 15) / 8 = 150 / 8 = 18.75
c. To find the mean without the outlier, remove the outlier from the data set and perform the same calculations:
(21 + 13 + 13 + 13 + 23 + 25 + 15) / 7 = 113 / 7 = 16.14
3. For this question, the data related to how each student in a class traveled to school in the morning is not given. Please provide the data so I can create a frequency table for you.
1. To find the mean, median, mode, and range of the given data set (-9, -36, -23, -8, -17, -52, -27, and -36), we can follow these steps:
a. Mean: The mean is calculated by summing up all the numbers in the data set and then dividing the sum by the total number of values.
Mean = (-9 - 36 - 23 - 8 - 17 - 52 - 27 - 36) / 8
Mean = -208 / 8
Mean = -26
b. Median: The median is the middle value in a sorted list of numbers. To find the median, we first need to order the data set in ascending order:
-52, -36, -36, -27, -23, -17, -9, -8
Since there are 8 numbers in the data set, the middle two numbers are -27 and -23. To find the median, we take the average of these two numbers:
Median = (-27 - 23) / 2
Median = -25
c. Mode: The mode is the value that appears most frequently in a data set. In this case, there is no value that appears more than once, so there is no mode.
d. Range: The range is the difference between the largest and smallest values in a data set. In this case, the largest value is -8 and the smallest value is -52.
Range = -8 - (-52)
Range = 44
2. Given the data set 21, 13, 13, 37, 13, 23, 25, 15, we can answer the questions as follows:
a. Outlier: An outlier is a value that is significantly different from other values in a data set. To identify the outlier, we can examine the data set and look for values that appear to be unusually large or small compared to the others. In this case, the number 37 stands out as being larger than the others, so it can be considered an outlier.
b. Mean with the outlier: To find the mean with the outlier, we sum up all the numbers in the data set, including the outlier, and then divide by the total number of values.
Mean = (21 + 13 + 13 + 37 + 13 + 23 + 25 + 15) / 8
Mean = 160 / 8
Mean = 20
c. Mean without the outlier: To find the mean without the outlier, we sum up all the numbers in the data set, excluding the outlier, and then divide by the total number of values.
Mean = (21 + 13 + 13 + 13 + 23 + 25 + 15) / 7
Mean = 123 / 7
Mean ≈ 17.57
3. In order to determine which frequency table represents the set of data related to how each student in a class traveled to school in the morning, we would need to provide the options for the frequency tables. Once the options are provided, I can help you determine the correct frequency table.