A length of a cable 26.48 long is cut into 4 equal part.what is the length of each piece
what is 26.48/4?
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26.48/4=
A length of a cable 14.48m long is cut into 4 equal pieces. What is the length of each piece
The expression can be simplified as:
10x^7 y^3 / (2x^3 y^2)
To simplify further, we can divide the numerator and denominator by the greatest common factor, which is 2x^3 y^2:
10x^7 y^3 / (2x^3 y^2) = (10/2) (x^7 / x^3) (y^3 / y^2)
Simplifying the exponents:
= 5x^(7-3) y^(3-2)
= 5x^4 y
Therefore, the simplified expression is 5x^4y.
2³x=2exponent5x-9.find x
10exponentx=10000.find x
2^(3x) = 2^(5x-9)
3x = 5x-9
2x = 9
x = 9/2
10^x = 10000 = 10^4
x = 4
To find the length of each piece of the cable, we can divide the total length of the cable by the number of pieces it is divided into.
Length of each piece = Total length of cable / Number of pieces
Length of each piece = 14.48 m / 4
Length of each piece = 3.62 m
Therefore, each piece of the cable is 3.62 meters long.
10x to the power7 y to the power3 over 2x to the power3 and y to the power2
Ages(19,24,29,34,39,44)
Number of works(3,7,8,4,5,3)
Calculate the mean age of the workers?Correct to the one decimal place
To find the mean age of the workers, we need to calculate the sum of the ages and divide by the total number of workers.
First, we can find the sum of the ages by multiplying each age by the number of workers and adding up the products:
Sum of ages = (19 x 3) + (24 x 7) + (29 x 8) + (34 x 4) + (39 x 5) + (44 x 3)
Sum of ages = 57 + 168 + 232 + 136 + 195 + 132
Sum of ages = 920
Next, we can find the total number of workers by adding up the number of workers:
Total number of workers = 3 + 7 + 8 + 4 + 5 + 3
Total number of workers = 30
Finally, we can find the mean age by dividing the sum of the ages by the total number of workers:
Mean age = Sum of ages / Total number of workers
Mean age = 920 / 30
Mean age = 30.67
Therefore, the mean age of the workers is 30.7 (correct to one decimal place).