Two resistors of resistances 3 ohms and 6 ohms are connected in a parallel across a 9 V battery. What is the equivalent resistance and the total current in the circuit?

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  1. conductance=1/3+1/9=4/9

    current= 9/(9/4)=4amps

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  2. current through 3 ohms = 9/3 = 3 amps
    current through 6 ohms = 9/6 = 1.5 amps
    total current = 4.5 amps
    equivalent R =V/i = 9/4.5 = 2 Ohms

    or of course
    1/R = 1/3+1/6 = 3/6
    so R = 6/3 = 2

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  3. Req = R1*R2/(R1+R2) = 3*6/(3+6) = 2 Ohms.

    I = E/R = 9/2 = 4.5 Amps.

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  4. I agree, I read the 6 as 9, ...

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  5. R=2ohms
    I=4.5A therefore, i agree to bobpursley's answer

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