Two planes start at 11AM from two airports 1800 miles apart, and fly toward each other at average rates of 200 and 250 miles per hour. the time at which they pass each other will be?

Question

Two planes start at 11AM from two airports 1800 miles apart, and fly toward each other at average rates of 200 and 250 miles per hour. the time at which they pass each other will be?

(A)4:30 PM
(B)2:30 PM
(C)2 PM
(D)3 PM

Answer 1

d 3pm.

the guy (unowen) above me did it correctly but forgot that it was asking for the time the planes met. 4 hours added onto 11 am is 3pm, thus answer choice d

Answer 2

Let n be the time between the planes leaving and then meeting each other. Then

200n+250n=1800
450n=1800
n=4 hours
☺☺☺☺

Answer 3

To find the time at which the two planes pass each other, we can use the formula:

Time = Distance / Speed

Let's calculate the time it takes for each plane to travel a distance of 1800 miles:
For the first plane:
Time1 = Distance1 / Speed1 = 1800 / 200 = 9 hours

For the second plane:
Time2 = Distance2 / Speed2 = 1800 / 250 = 7.2 hours

Now, let's determine the total time it takes for both planes to meet each other:
Total Time = Time1 + Time2 = 9 + 7.2 = 16.2 hours

Since the planes started at 11 AM, we need to add 16.2 hours to that time. Let's convert the hours into minutes:
16 hours = 16 * 60 = 960 minutes
0.2 hours = 0.2 * 60 = 12 minutes

So, the total time is 960 minutes + 12 minutes = 972 minutes.

Now, let's convert the total minutes into hours and minutes:
972 minutes / 60 = 16 hours remainder 12 minutes

Finally, we can determine the time at which the planes pass each other by adding the calculated time to the starting time:
11 AM + 16 hours = 3 PM

Therefore, the two planes will pass each other at 3 PM (Option D).