If v=t^2-2t+1. Find s given that v=4 when t=1.
This makes no sense to me. What is "s"?
v cannot equal 4 when t = 1. When t = 1:
v = t^2 - 2t + 1 = 1 - 2 + 1 = 0.
Please check the problem statement.
"s" do you mean solution. Goodness, s is not a standard abbreviation.
v=4 when t=1 is not possible.
Now trying to decipher your cryptic problem statement.
is v velocity? Is s displacement? I can't imagine anyone assigning this without saying that. Even with that, it still makes no sense to me.
It is (somewhat) clearly a motion problem.
v(t) = t^2-2t+1
s(t) = 1/3 t^3 - t^2 + t + C
Now, knowing that v(1) = 4 does not help to find C.
Moreover, given the equation, it is clear that v(1)=0, not 4. So, let's assume that s(1) = 4. Then we have
1/3 - 1 + 1 + C = 4
C = 3 2/3 = 11/3
s(t) = 1/3 t^3 - t^2 + t + 11/3
If that is an incorrect interpretation of your garbled question, maybe you can fix it and the arrive at the solution.
To find the value of s when v = 4 and t = 1, we need to substitute these values into the equation v = t^2 - 2t + 1.
Step 1: Start with the given equation v = t^2 - 2t + 1.
Step 2: Substitute t = 1 and v = 4 into the equation.
v = 1^2 - 2(1) + 1
= 1 - 2 + 1
= 0.
Step 3: Simplify the equation to find the value of s.
0 = s - 2(1) + 1
= s - 2 + 1
= s - 1.
Step 4: Now, isolate s by adding 1 to both sides of the equation.
0 + 1 = s - 1 + 1
= s.
Step 5: Simplify the equation to find the value of s.
1 = s.
Therefore, when v = 4 and t = 1, the value of s is 1.