x^2+x=12
Since you do not ask a specific question, I assume that you want to find the factors.
x^2 + x - 12 = 0
From the above, for the center term, you are looking for two values whose product is -12 and whose sum is +1.
(x + 4)(x - 3) = 0
I hope this helps. Thanks for asking.
To solve the equation x^2 + x = 12, we need to find the values of x that make the equation true.
Step 1: Rewrite the equation in the standard form ax^2 + bx + c = 0, where a, b, and c are coefficients. In this case, the equation is already in standard form.
Step 2: Factor the quadratic equation, if possible. In this case, the equation can be factored as (x + 4)(x - 3) = 0.
Step 3: Set each factor equal to zero and solve for x.
First factor: x + 4 = 0. Solving for x, we get x = -4.
Second factor: x - 3 = 0. Solving for x, we get x = 3.
So, the solutions to the equation x^2 + x = 12 are x = -4 and x = 3.