The maximum horizontal range of a projectile is given by the formula R=u^2/g, where u is the initial velocity and g is the acceleration due to gravity. Find the velocity with which a ball can be thrown to have a maximum range of 20 meters when the acceleration due to gravity is equal to 9.8 m/s.
My answer: 20=u^2/9.8
118=u^2
u=10.8
Am I correct?
Thanks For Checking
No, no, no.
20*9.8 is NOT 118, recheck that
To find the velocity with which a ball can be thrown to have a maximum range of 20 meters, we can start by rearranging the formula R = u²/g to solve for u.
The formula R = u²/g represents the maximum horizontal range of a projectile. In this formula, R is the maximum range, u is the initial velocity, and g is the acceleration due to gravity.
Given that R = 20 meters and g = 9.8 m/s², we can substitute these values into the formula:
20 = u² / 9.8
To solve for u, we can multiply both sides of the equation by 9.8:
20 * 9.8 = u²
196 = u²
Now, we can take the square root of both sides to isolate u:
√196 = √(u²)
14 = u
Therefore, the velocity with which the ball can be thrown to have a maximum range of 20 meters when the acceleration due to gravity is equal to 9.8 m/s² is 14 m/s.
So, your answer, u = 14, is correct.