when solving the exponential equation, 2^2x-1=16 what do I do first? do I convert to a log equation?

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asked by Sanya
  1. I would take the log base 2 of each side.

  2. I think you mean 2^(2x-1) = 16

    taking logs would be the hard way of doing it.
    Notice that 16 is a power of 2, namely 16 = 2^4
    so 2^(2x-1) = 2^4

    clearly 2x-1 = 16
    x = 17/2

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    posted by Reiny
  3. <clearly 2x-1 = 16>

    I meant to type

    clearly 2x-1 = 4

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    posted by Reiny

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