two forces are in the ratio 1:2 named p and q.if their resultant is at an angle tan inverse root 3 /2 to vector p then the angle between p and q is ?
first find the angle:
tan^-1 Theta=3/2 draw a right triangle, opposite side 3, adjacent 2, then hypotenuse is sqrt5
Sin Theta=3/sqrt5 from the drawing.
Law of sines:
2/sinTheta=1/sinLastangle
where last angle is between resultant and side 2
sinlast angle=1.5 /sqrt5
put this into your google search engine:
inverse sine(1.5 /sqrt 5) in degrees=
Now, determine the last angle:
angle between p and q is 180-lastangle-givenagnle