chemistry

help required in calculating the pH value of a .84 mols per litre solution of sulfuric acid. I understand that pH = -log 10 (2x 0.84), I am not very experienced with logs and need assistance as to which keys to press on the scientific calculator in relation to the logs. thank in advance.

Learn your calculator.

all are different.

put this in the Google Search window:

-log(2*.84)

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