Your class hopes to collect at least 325 cans of food for the annual food drive. There were 135 cans donated the first week and 89 more the second week.
a. Write an inequality that describes this situation. Let c represent the number of cans of food that must be collected by the end of the third week of your class to meet or surpass its goal.
b. How many cans are needed to meet or surpass the goal?
c >/= 325 - 135 - 89
c >/= 101
so 101 or more
A. 135+89+C=325
B. 224+C>=325
-224 -224
C>=101
I have answers is right
a.) 135 + 89 + C ≥ 325
224 + C ≥ 325
b.) 224 + C ≥ 325
C ≥ 325 - 224
C ≥ 10
a. Let c represent the number of cans of food collected by the end of the third week. The inequality that describes this situation is:
c >= 325 - (135 + 89)
b. To meet or surpass the goal, the number of cans needed can be calculated by:
c >= 325 - (135 + 89)
c >= 325 - 224
c >= 101
Therefore, at least 101 cans are needed to meet or surpass the goal.
a. To write an inequality that describes this situation, we can use the expression "c ≥ 325", where c represents the number of cans of food that must be collected by the end of the third week. The symbol "≥" stands for "greater than or equal to", indicating that the number of cans collected should be equal to or greater than 325 to meet or surpass the goal.
b. To determine how many cans are needed to meet or surpass the goal, we need to find the difference between the goal (325 cans) and the number of cans already collected (135 + 89).
135 + 89 = 224
So, we can subtract 224 from the goal to find the number of cans needed:
325 - 224 = 101
Therefore, a minimum of 101 more cans are needed to meet or surpass the goal.