How many grams should be to taken to make 0.5 molar sodium bicarbonate in 100ml soiution.
To find out how many grams of sodium bicarbonate (NaHCO3) should be taken to make a 0.5 molar solution in 100 mL, we need to use the equation:
Molarity (M) = moles of solute / volume of solution (L)
First, let's convert the volume of the solution to liters:
Volume of solution = 100 mL = 100/1000 L = 0.1 L
Next, we can rearrange the equation to solve for moles of solute:
moles of solute = Molarity * volume of solution
moles of solute = 0.5 M * 0.1 L = 0.05 moles
Finally, to find out how many grams of sodium bicarbonate are needed, we need to use its molar mass. The molar mass of sodium bicarbonate is calculated as:
Na = 22.99 g/mol
H = 1.01 g/mol
C = 12.01 g/mol
O = 16.00 g/mol
Molar mass of NaHCO3 = (22.99) + (1.01) + (12.01) + (3 * 16.00) = 84.01 g/mol
To calculate the mass, we can use the equation:
mass = moles of solute * molar mass
mass = 0.05 moles * 84.01 g/mol
So, to make the 0.5 molar sodium bicarbonate solution in 100 mL, you would need to take 4.2 grams of sodium bicarbonate.