(2x-1)(3x-7)(4x+3)
=6x^2-14x-33x+7
=(6x^2-19x+7)(4x+3)
=24x^3+18x^2-126x+28x+21
=24x^3+18x^2-88x+21 <-- my answer
but the correct answer is 24x^3-50x^2-23x+21
please correct me? thank you!
(2x-1)(3x-7) = 6x^2-17x+7
go to calc101.com and click on the long division button.
Enter 6x^2-17x+7 and 4x+3 as your polynomials, and watch the fun! I'm sure you will find where you went wrong.
Sorry, make that the long multiplication button.
(3x-7)(4x+3) = 12 x^2 -19 x - 21
now use distributive property
2x (12 x^2 -19 x - 21)
-1 (12 x^2 -19 x - 21)
= 24 x^3 - 38 x^2 - 42 x
_________- 12 x^2 + 19 x + 21
===============================
= 24 x^3 - 50 x^2 - 23 x + 21
here is the link Steve is sending you to (I went and looked(
http://calc101.com/webMathematica/long-multiply.jsp
amazing - it got the same thing I did :)
To find the correct answer, we need to multiply the binomials (2x-1) and (3x-7) first, and then multiply the resulting expression with (4x+3).
Let's break it down step by step:
Step 1: Multiply the first two binomials (2x-1) and (3x-7) using the distributive property.
(2x-1)(3x-7) = 2x * 3x + 2x * (-7) - 1 * 3x - 1 * (-7)
= 6x^2 - 14x - 3x + 7
= 6x^2 - 17x + 7
Step 2: Now, we need to multiply the result from Step 1 with (4x+3).
(6x^2 - 17x + 7)(4x+3) = 6x^2 * 4x + 6x^2 * 3 + (-17x) * 4x + (-17x) * 3 + 7 * 4x + 7 * 3
= 24x^3 + 18x^2 - 68x^2 - 51x + 28x + 21
= 24x^3 - 50x^2 - 23x + 21
So, the correct answer is 24x^3 - 50x^2 - 23x + 21.