A square vessel of sides 0.2m x 0.1 m is filled with alchol od density 900 kg m raised to -3 upto a level of 0.5 m. what is the pressure and thrust on the bottom of vessel? Giving g = m s raised -2 .
.2 m square or .1 m square on bottom?
I will assume bottom square size s
and depth h
pressure = density * g * h
if h is .5 m (it is not clear what depth of alcohol is from sloppy wording of question. It is the depth that matters, not how high the container is off the ground.)
pressure = 900 kg/m^3 * 9.81 m/s^2 * .5 m
= 4414 N/m^2 or Pascals above atmospheric pressure which is about 100,000 N/m^2 or Pascals
Since atmospheric pressure also pushes up on the bottom, the net force is
4414 N/m^2 * area of bottom = 4414 s^2 Newtons