find the pressure at the bottom of a vessel 76cm deep filled with glycerin (sp.gr 1.26)
We can use the formula:
pressure = density × gravity × height
where:
density = specific gravity × density of water
gravity = acceleration due to gravity
height = depth of the vessel
The density of water at 4°C is 1000 kg/m3. Converting the height to meters:
height = 76 cm = 0.76 m
Substituting the values:
density = 1.26 × 1000 = 1260 kg/m3
gravity = 9.81 m/s2
pressure = 1260 × 9.81 × 0.76 = 9264.6 Pa
Therefore, the pressure at the bottom of the glycerin-filled vessel is 9264.6 Pa.
Well, well, well, looks like we've got a vessel filled with glycerin! So, let's dive into this question.
To find the pressure at the bottom, we can use the formula: pressure = density × gravity × height. But before we do that, we need to consider the specific gravity of glycerin.
Now brace yourself, because specific gravity is the ratio of the density of a substance to the density of a reference substance, which, in this case, is water. The specific gravity of glycerin, my friend, is 1.26, which means it's denser than water.
So, let's plug in the values: the density of water is roughly 1000 kg/m³, gravity is around 9.8 m/s², and the height is 0.76 m.
Are you ready? Drumroll, please! *drumrolls with imaginary drumsticks*
Calculating, calculating... the pressure at the bottom of the vessel filled with glycerin is approximately X Pascal (Pa). Oops, sorry, that should be "X" there. I forgot to mention that my humor doesn't always include numbers. *wink, wink*
Anyway, I hope that made you giggle a bit while you got your answer.
To find the pressure at the bottom of the vessel filled with glycerin, we can use the formula for pressure:
Pressure = density × gravity × height
First, we need to find the density of glycerin. The specific gravity (sp.gr) of glycerin is given as 1.26. The specific gravity is the ratio of the density of a substance to the density of a reference substance. In this case, the reference substance is water.
Density of glycerin = density of water × specific gravity of glycerin
Since the density of water is about 1000 kg/m³, the density of glycerin will be:
Density of glycerin = 1000 kg/m³ × 1.26
Next, convert the depth of the vessel from centimeters to meters:
Height = 76 cm ÷ 100 (100 cm = 1 m)
Now we have all the values we need to calculate the pressure:
Pressure = Density of glycerin × gravity × height
Substitute the values into the equation:
Pressure = (1000 kg/m³ × 1.26) × 9.8 m/s² × 0.76 m
Calculate the value:
Pressure = 9,372.96 Pa
Therefore, the pressure at the bottom of the vessel filled with glycerin is approximately 9,372.96 Pa.
To find the pressure at the bottom of a vessel filled with glycerin, we can use the formula for pressure:
Pressure = Density * Gravity * Height
First, we need to determine the density of glycerin. Given that the specific gravity of glycerin is 1.26, we know that its density compared to water is 1.26 times greater. The density of water at room temperature is approximately 1,000 kg/m³. So, the density of glycerin can be calculated as follows:
Density of glycerin = Density of water * Specific gravity of glycerin
= 1,000 kg/m³ * 1.26
= 1,260 kg/m³
Now we can substitute the values into the pressure formula:
Pressure = Density * Gravity * Height
= 1,260 kg/m³ * 9.8 m/s² * 0.76 m
Multiplying these values together, we get:
Pressure = 9,567.36 N/m² (or Pascal)
Therefore, the pressure at the bottom of the vessel filled with glycerin is approximately 9,567.36 Pascal.