A beaker weigh 0.4 Newton when empty and 1.4 Newton when filled water. What does it weigh when filled with Brine of density 1.2 g/cm³ (density of water is 1g/cm³)
since the water weighed 1.0N, an equal amount of brine will weigh 1.2 times as much.
it will weigh 0.4 + 1.2*1.0 = 1.6 N
Well, it seems the beaker is quite the lightweight when it's empty, weighing only 0.4 Newton. But when filled with water, it gains some water weight and clocks in at 1.4 Newton. Now, if we swap out the water for brine, which has a density of 1.2 g/cm³ compared to water's 1 g/cm³, I can just imagine the beaker bulking up with all that extra saltiness. Considering the added density, I would say it might weigh somewhere between "Oops, I added too much salt" and "I think I just broke my kitchen scale."
To calculate the weight of the beaker when filled with brine, you need to consider the weight of the brine itself.
Given:
Weight of the empty beaker = 0.4 Newton
Weight of the beaker when filled with water = 1.4 Newton
To find the weight of the brine, we need to find the weight of the water and subtract it from the total weight of the beaker when filled with water.
Weight of the water = Weight of the beaker when filled with water - Weight of the empty beaker
= 1.4 N - 0.4 N
= 1 N
Now, let's calculate the volume of the brine.
Density of water = 1 g/cm³
Density of brine = 1.2 g/cm³
The density of a substance is mass per unit volume. Since the density of the brine is given in g/cm³, we need to convert the weight of the water to mass by using the density of water.
Mass of the water = Weight of the water / Acceleration due to gravity
= 1 N / 9.8 m/s² (approximate value of acceleration due to gravity)
≈ 0.102 kg (using the approximate value)
The volume of the water can be calculated using the mass and density of water.
Volume of the water = Mass of the water / Density of water
= 0.102 kg / 1 g/cm³
= 102 cm³
Now, let's calculate the weight of the brine by considering its density.
Weight of the brine = Volume of the brine * Density of brine
= Volume of the water * Density of brine
= 102 cm³ * 1.2 g/cm³
= 122.4 g
To convert the weight from grams to Newtons, we need to multiply it by the acceleration due to gravity. Using the approximate value of the acceleration due to gravity (9.8 m/s²), we can convert the weight to Newtons.
Weight of the brine in Newtons = (Weight of the brine in grams / 1000) * Acceleration due to gravity
= (122.4 g / 1000) * 9.8 m/s²
= 1.1992 N (approximate value)
Therefore, the weight of the beaker when filled with brine of density 1.2 g/cm³ is approximately 1.1992 Newtons.
To find the weight of the beaker when filled with brine, you need to consider the change in weight due to the difference in density between the water and the brine.
Here's how you can calculate it step by step:
Step 1: Convert the densities from g/cm³ to kg/m³
Given:
Density of water = 1 g/cm³ = 1000 kg/m³
Density of brine = 1.2 g/cm³ = 1200 kg/m³
Step 2: Calculate the volume of water in the beaker
The difference in weight between the empty beaker and the beaker with water is 1.4 N - 0.4 N = 1 N.
Since the density of water is 1000 kg/m³, the volume of water in the beaker can be calculated using the formula:
volume = weight / density
volume of water = 1 N / 1000 kg/m³ = 0.001 m³
Step 3: Calculate the weight of the brine
The volume of the beaker remains the same when filled with brine. Therefore, you can calculate the weight of the brine using the formula:
weight = volume * density
weight of brine = 0.001 m³ * 1200 kg/m³ = 1.2 N
Therefore, the weight of the beaker when filled with brine is 1.2 Newtons.