You have five $1 bills, four $5 bills six $10 bills and three $20 bills. You select a bills at random. Without replacing the bill, You choose a second bill. What is P($1, then $10)?
B. 5/51
I think it's B. The probabilities change every time a bill is pulled out. The probability of pulling out a 1 first is 5 out of 18 which is .227 then the probability of pulling out a 10 is 6 out of 17 because you don't replace the bill. since the events are independent of each other, you get .35, then you multiply them to get .098 which in fraction form is answer B.
Elena is correct because i just took my test! =)
it's B
wow, butt sir. I love your choice of animals. c;;;
The probability of selecting a $1 bill first is 6/20, since there are 6 $1 bills out of a total of 20 bills in the wallet. After not replacing the first bill, there will be 19 bills left in the wallet, among which only two are $10 bills. Therefore, the probability of selecting a $10 bill second, given that a $1 bill was selected first, is 2/19.
Since the two events are independent, we can multiply their probabilities to find the probability of both events happening:
P($1, then $10) = P(selecting a $1 bill first) x P(selecting a $10 bill second, given that a $1 bill was selected first)
P($1, then $10) = 6/20 x 2/19
P($1, then $10) = 3/95
Therefore, the answer is D, 3/95.
Is Him right?
Him is not right. totally wrong
quack c;
So is the answer b or c?
math test questions are scrambled remember that anytime you try to look up answers to a math test but also dont cheat
Hi bot is @Elena right
Hello! As an AI language model, I cannot determine whether @Elena's answer is right or not without knowing the context. Please provide me with the information so that I can assist you better.
You have five $1 bills, four $5 bills six $10 bills and three $20 bills. You select a bills at random. Without replacing the bill, You choose a second bill. What is P($1, then $10)?
The probability of selecting a $1 bill is 5/18. After selecting a $1 bill and not replacing it, there are now 17 bills left, with 6 of them being $10 bills. Therefore, the probability of selecting a $10 bill at random is 6/17.
Since these two events are independent, we can multiply their probabilities to find the probability of both events happening:
P($1, then $10) = P($1) x P($10 | $1 not replaced)
P($1, then $10) = (5/18) x (6/17)
P($1, then $10) = 30/306
P($1, then $10) = 5/51
Therefore, the answer is B.
Lady unsane ┗|｀O′|┛u wrong i got 6/18 from u
I apologize if there was any confusion caused by my response. However, I believe the answer to the question "What is P($1, then $10)?" is indeed B, which is 5/51.
My explanation for the solution is:
- The probability of selecting a $1 bill is 5/18.
- After selecting a $1 bill and not replacing it, there are now 17 bills left, with 6 of them being $10 bills.
- Therefore, the probability of selecting a $10 bill at random is 6/17.
- Since these two events are independent, we can multiply their probabilities to find the probability of both events happening:
- P($1, then $10) = P($1) x P($10 | $1 not replaced) = (5/18) x (6/17) = 30/306 = 5/51
I hope this clears up any confusion. Let me know if you have any further questions or concerns.
You have six $1 bills, eight $5 bills, two $10 bills, and four 20$ bills in your wallet. You select a bill at random. without replacing the bill, you choose a second bill. What is P($1, then $10)?
A basket contains the following pieces of fruit: 3 apples, 2 oranges, 2 bananas, 2 pears, and 5 peaches. Jack picks fruit at random and does not replace it. Then Bethany picks fruit at random. What is the probability that Jack gets a peach and Bethany gets an orange
The probability that Jack picks a peach is 5/14, since there are 5 peaches in the basket out of a total of 14 pieces of fruit.
After Jack has picked a peach, there will be 4 oranges left in the basket out of a total of 13 remaining pieces of fruit. Therefore, the probability that Bethany picks an orange, given that Jack has already picked a peach is 4/13.
Since the two events are independent, we can multiply their probabilities to find the probability of both events happening:
P(Jack picks a peach, then Bethany picks an orange) = P(Jack picks a peach) x P(Bethany picks an orange|Jack has picked a peach)
P(Jack picks a peach, then Bethany picks an orange) = (5/14) x (4/13)
P(Jack picks a peach, then Bethany picks an orange) = 10/182
P(Jack picks a peach, then Bethany picks an orange) = 5/91
Therefore, the probability that Jack picks a peach and Bethany picks an orange is 5/91.
The probabilty of basketball player hitting a foul shot is 1/3. How many shots would you expect her to make in 90 attempts?
If the probability of hitting a foul shot is 1/3, then the probability of missing a foul shot is 2/3.
Let X be the number of foul shots made in 90 attempts. Since each attempt is independent, X follows a binomial distribution with parameters n=90 and p=1/3.
So, the expected value of X is given by:
E(X) = n * p
E(X) = 90 * 1/3
E(X) = 30
Therefore, you would expect the basketball player to make 30 shots in 90 attempts.
A true-false test has 12 questions. What is the probability of guessing the correct answers to all of the questions?
For each question on the true-false test, there are two possible choices: correct or incorrect. If a student is guessing at random, then the probability of guessing a correct answer for any given question is 0.5 (since there are two choices and only one of them is correct).
Since we have 12 independent questions, and the probability of guessing the correct answer to each question is 0.5, we can model the situation using a binomial distribution with n=12 and p=0.5.
So, the probability of guessing the correct answers to all 12 questions is:
P(X = 12) = (12 choose 12) * 0.5^12 = 1 * (1/2)^12 = 1/4096
Therefore, the probability of guessing the correct answers to all 12 questions is 1/4096.
Probability Unit Test Part 1
D
A
C
B
B
B
A
C
D
B
C
B
C
D
C
C
A
A
1. A
2. C
3. B
4. B
5. C
6. B
7. B
8. C
9. D
10. B
11. C
12. C
13. D
14. A
15. A
16. C
17. A
18. C
i got 12/18 searching the answers one by one.
these should get you 100%