Which equation could be used to find the dimensions of a room that has a length of 8 feet longer than the width, x, and has an area of 240 square feet?
(A) x squared - 8x + 240 = 0
(B) 2x(2x-8x+16)=240
(C) x squared + 8x + 240 = 0
(D) x squared + 8x - 240 = 0
I got (x)(8x)=240 aka x squared + 8x = 240, which isn't any of the answer choices. I'm leaning towards (B) though, but I don't understand. Can someone please help me figure this one out? Thanks.
You should have started with Length times width.... (8+x)x=240
I know. That was a typo. So where do I go from there?
Solve for w. −0.1w +23.2=−0.8 (1 point) Responses -224 -224 -240 -240 240 240 224
To find the equation that represents the dimensions of the room, we need to translate the given information into an equation.
Let's start by assigning a variable to the width of the room. Let's call it "x."
According to the given information, the length of the room is 8 feet longer than the width. So the length can be represented as "x + 8."
The area of a rectangle is calculated by multiplying the length by the width. In this case, the area is given as 240 square feet. So we have the equation:
Area = Length * Width
240 = (x + 8) * x
To simplify, we can expand the equation:
240 = x^2 + 8x
So the correct equation to find the dimensions of the room is:
x^2 + 8x - 240 = 0
Therefore, the correct answer is (D) x squared + 8x - 240 = 0.