The perimeter of a room is 50m.The length exceeds the width by 3.3m.Find the length of the room.

L + W = 50 / 2

L = W + 3.3

substituting ... W + 3.3 + W = 25
... solve for W ... then substitute back to find L

Why did the room go on a diet? Because it wanted to get in shape and have a smaller perimeter! Anyway, let's solve the mystery of the room's length. Let's say that the width of the room is "w" meters. Since the length exceeds the width by 3.3 meters, we can call the length "w + 3.3" meters.

To find the perimeter, we add up all the sides:
Perimeter = 2w + 2(w + 3.3)

Now we can use the information given that the perimeter is 50 meters to solve for "w":
50 = 2w + 2(w + 3.3)

Simplifying the equation, we have:
50 = 2w + 2w + 6.6
50 = 4w + 6.6
43.4 = 4w
w = 10.85

So, the width of the room is approximately 10.85 meters. Since the length is w+3.3, the length of the room is approximately 14.15 meters (10.85 + 3.3).

Hope that brings a smile to your face, just like the room finding its dimensions!

Let's assume the width of the room is "W" meters.

Given that the length exceeds the width by 3.3 meters, we can express the length as (W + 3.3) meters.

The perimeter of a rectangle is given by the formula: Perimeter = 2(length + width).

In this case, the perimeter is given as 50 meters.

So, we can write the equation as:

50 = 2((W + 3.3) + W)

Simplifying the equation, we have:

50 = 2(2W + 3.3)

Now, let's solve for W:

50 = 4W + 6.6

Subtracting 6.6 from both sides:

50 - 6.6 = 4W

43.4 = 4W

Dividing both sides by 4:

43.4/4 = W

W ≈ 10.85

Therefore, the width is approximately 10.85 meters.

To find the length, we can substitute the width value back into the equation:

Length = Width + 3.3

Length = 10.85 + 3.3

Length ≈ 14.15

Therefore, the length of the room is approximately 14.15 meters.

To find the length of the room, we can use the information given.

Let's assume the width of the room is "w" meters. According to the problem, the length exceeds the width by 3.3 meters. Therefore, the length can be represented as "w + 3.3" meters.

The perimeter of a rectangle is calculated by adding the length of all four sides together. In this case, the perimeter is given as 50 meters.

Perimeter = 2 * (length + width)

Substituting the values we have:

50 = 2 * (w + 3.3 + w)

Now, let's simplify the equation:

50 = 2 * (2w + 3.3)

50 = 4w + 6.6

Subtracting 6.6 from both sides of the equation:

50 - 6.6 = 4w

43.4 = 4w

Finally, we divide both sides of the equation by 4:

43.4 / 4 = w

w ≈ 10.85

So, the width of the room is approximately 10.85 meters. The length of the room is the width plus 3.3:

Length = 10.85 + 3.3

Length ≈ 14.15

Therefore, the length of the room is approximately 14.15 meters.