Please help me to understand what it is that I need to do. A rectangle whose length is 5.3 cm and whose width is 2.5 cm
So? What are you supposed to do with this rectangle? Find the perimeter? Find the area? Or??
Hello Ms. SUe I am new to Pre-Algebra. I am not sure this is why I am trying to understand the step so I can do my homework. Can you explain because that is all the instruction say so I am not sure what to do with the I suppose so. Not sure that why I am confused.
Yes find the perimeter , Sorry.
If that is all the instructions say, ask your teacher about it.
But I'll bet that you've overlooked part of the instructions. Please look again.
Yes, andThank you
You're welcome.
To understand what you need to do with a rectangle whose length is 5.3 cm and width is 2.5 cm, you can follow these steps:
1. Determine the area of the rectangle:
- The area of a rectangle is calculated by multiplying its length by its width.
- In this case, the length is 5.3 cm and the width is 2.5 cm.
- Multiply the length and width: 5.3 cm * 2.5 cm = 13.25 square cm.
- So, the area of the rectangle is 13.25 square cm.
2. Calculate the perimeter of the rectangle:
- The perimeter of a rectangle is the sum of all its sides.
- In this case, there are two pairs of sides, each side being equal to the length and width.
- Add up all the sides of the rectangle: 5.3 cm + 2.5 cm + 5.3 cm + 2.5 cm = 15.6 cm.
- So, the perimeter of the rectangle is 15.6 cm.
Now, you should have a better understanding of what you can do with a rectangle having a length of 5.3 cm and a width of 2.5 cm, which includes calculating its area and perimeter.