Your middle school is having a fall carnival. Admission into the carnival is $3 and each game inside the carnival costs .25 cents.Write and inequality that represents the possible number of games that can be played having 10 dollars. What is the maximum number of games that can be played? I know that it is one of these next two choices, but I am not sure which one.Thank you.
(A) 0.25x+3 less than 10; 28 games
(B) 0.25x+3 less than or equal to 10; 28 games
b. .25x+3<=10 as he can spend all ten dollars.
The answer would be B.
To determine the inequality that represents the possible number of games that can be played with $10, let's break down the problem step by step:
1. The admission fee into the carnival is $3. So, you will have $10 - $3 = $7 left to spend on games.
2. Each game costs $0.25, and we want to find the maximum number of games that can be played with $7.
3. We can represent the number of games as "x." Therefore, the cost of the games can be expressed as 0.25x.
4. To find the maximum number of games, we need to find the largest possible value of x that satisfies the given condition.
5. The total amount spent on games and the admission fee should be less than or equal to $10.
6. So, the inequality that represents the possible number of games that can be played is 0.25x + 3 ≤ 10.
Now, let's calculate the maximum number of games that can be played:
0.25x + 3 ≤ 10
Subtract 3 from both sides:
0.25x ≤ 7
To remove the decimal, multiply both sides by 100:
25x ≤ 700
Divide both sides by 25:
x ≤ 28
Therefore, the maximum number of games that can be played is 28.
So, the correct choice is (B) 0.25x + 3 ≤ 10; 28 games.