paul is twice as old as john.17years ago their age was 33.how old is paul?
what do you mean by "their age" ?
must be combined age?
p = 2 j
p-17 + j-17 = 33
p + j = 67
2 j + j = 67
3 j = 67
j = 67/3 = 22 1/3
so
p = 134/3 = 44 2/3
To determine the age of Paul, we need to follow a logical approach using the given information.
Let's assume John's current age is J years and Paul's current age is P years.
According to the first statement, Paul is twice as old as John:
P = 2J
Now, 17 years ago, their age was 33. So, we need to subtract 17 from their current ages:
John's age 17 years ago = J - 17
Paul's age 17 years ago = P - 17
According to the second statement, their combined age 17 years ago was 33:
(J - 17) + (P - 17) = 33
Substituting P = 2J into the equation, we can solve for J:
(J - 17) + (2J - 17) = 33
Reorganizing the equation:
3J - 34 = 33
Adding 34 to both sides:
3J = 67
Dividing by 3:
J = 22.33
We rounded J to two decimal places since it is unlikely for someone to have an age in fractions.
Now, we can substitute J into the equation P = 2J to find Paul's age:
P = 2 * 22.33
P = 44.66
Again, we rounded P to two decimal places.
Therefore, Paul's current age is approximately 44.66 years old.