Suppose you have a wallet with $5 bills, $10 bills, and $20 bills. If the probability of picking a $20 bill is 4/15, and the probability of piciing a $5 bill is 1/3, what is the probability of picking a $20 bill?
a. 1/15
b. 1/5
c. 4/15
d. 2/5 **
15/15 - 4/15 - 5/15 = ?
Yes, 2/5 is right.
@Ms.Sue (THE FAKE ONE) is always making peoples grades bad, thanks. (<-- sarcasm)
you are correct.
Fake Mrs. Sue, at least learn to spell lol.
D IS CORRECT
is 2/5 correct?
Yes, 2/5 is correct.
To get this answer, you need to find the probability of picking a $20 bill by subtracting the probability of picking a $5 bill and the probability of picking a $10 bill from 1 (since these are the only three options).
So, 1 - 1/3 - x = 4/15, where x is the probability of picking a $10 bill.
Solving for x, you get x = 1/15.
Then, the probability of picking a $20 bill is 4/15 - 1/15 = 3/15 = 1/5.
To find the probability of picking a $20 bill, we can use the information given in the question.
Let's assign some variables:
Let P($20) represent the probability of picking a $20 bill.
Let P($5) represent the probability of picking a $5 bill.
According to the question, P($20) = 4/15 and P($5) = 1/3.
Now, to find the probability of picking a $20 bill, we need to subtract the probability of picking a $5 bill from 1.
Picking any bill from the wallet (including a $20 bill or a $5 bill) accounts for all possibilities. Therefore, the total probability of picking any bill should be equal to 1.
So, P($20) + P($5) = 1.
Substituting the known values, we have:
4/15 + 1/3 = 1.
To find P($20), we rearrange the equation:
P($20) = 1 - P($5).
P($20) = 1 - 1/3.
Now, let's calculate:
P($20) = 3/3 - 1/3.
P($20) = 2/3.
Therefore, the probability of picking a $20 bill is 2/3.
However, none of the given answer options match our calculation. Please double-check the answer choices provided.