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Maths

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What is the smallest possible positive integer x>5 , that leaves a remainder of 5 whenever it is divided by 14 , 8 or 77 ?

  • Maths -

    14 = 2x7
    8 = 2x2x2
    77 = 7x11

    LCM = 7x11x8 = 616

    adding 5+616 = 621

    check:
    621÷8 leaves remainder of 5
    621÷14 leaves remainder of 5
    621÷77 leaves remainder of 5

    the number is 621

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