# Maths

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What is the smallest possible positive integer x>5 , that leaves a remainder of 5 whenever it is divided by 14 , 8 or 77 ?

• Maths -

14 = 2x7
8 = 2x2x2
77 = 7x11

LCM = 7x11x8 = 616

check:
621÷8 leaves remainder of 5
621÷14 leaves remainder of 5
621÷77 leaves remainder of 5

the number is 621

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