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The temperature of a 12.58g sample of calcium carbonate increases from 23.6degrees celcius to 38.2 degrees celcius. If the heat capacity is 0.82J/g-K, how many Joules of heat are absorbed

  • Chemistry -

    Looks to me like the temp change is 14.6K, so

    .82J/gK * 12.58g * 14.6K = 150.6J

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