posted by Tommy .
The temperature of a 12.58g sample of calcium carbonate increases from 23.6degrees celcius to 38.2 degrees celcius. If the heat capacity is 0.82J/g-K, how many Joules of heat are absorbed
Looks to me like the temp change is 14.6K, so
.82J/gK * 12.58g * 14.6K = 150.6J