posted by Anonymous
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is:
S2(g)+C(s)<-> CS2(g) Kc=9.40 at 900K
How many grams of CS2(g) can be prepared by heating 16.8 moles of S2(g) with excess carbon in a 9.80 L reaction vessel held at 900 K until equilibrium is attained?