How many grams of Iodine, I2 must be dissolved in725ml of carbon disulfide, CS2 (d=1.261 g/ml), to produce a 0.236m solution?

8.37 g

m = moles/kg solvent

solve for moles.
Then moles = g/molar mass.
solve for grams.

To determine the number of grams of iodine (I2) needed to achieve a desired molarity in a given volume of a solvent, you can follow these steps:

Step 1: Convert the given volume of carbon disulfide (CS2) from milliliters (ml) to liters (L):

725 ml × (1 L / 1000 ml) = 0.725 L

Step 2: Calculate the number of moles of iodine (I2) needed using the molarity equation:

Molarity (M) = Moles of solute / Volume of solvent (in liters)

Rearrange the equation to solve for moles of solute:

Moles of solute = Molarity × Volume of solvent (in liters)

Moles of solute = 0.236 mol/L × 0.725 L = 0.1714 moles

Step 3: Find the molar mass of iodine (I2):

Iodine (I2) is diatomic, so its molar mass is the sum of two iodine atoms.

Atomic mass of iodine (I) = 126.90 g/mol

Molar mass of iodine (I2) = 2 × 126.90 g/mol = 253.80 g/mol

Step 4: Calculate the mass of iodine (I2) using the number of moles and molar mass:

Mass (g) = Moles × Molar mass

Mass (g) = 0.1714 mol × 253.80 g/mol = 43.57 g

Therefore, you would need approximately 43.57 grams of iodine (I2) to dissolve in 725 ml of carbon disulfide (CS2) to produce a 0.236M (mol/L) solution.