Algebra Multiple Choice
posted by Kris .
Hello,
This is the last of questions I have for my practice assignment. Again I will put what I got. Thanks for your help.
1.) Solve the system using substitution. Write answer as an ordered pair.
4x+2y=8
5x2=y
A.) First equation (2,8)
B.) Second equation (2,8)
I put A
2.) Solve the system using elimination. If the system is linearly dependent, state the general solution in terms of a parameter.
4x2y+2z=2
x+y3z=4
4x3y+7z=9
A.) (1,7,0)
B.) (3,3,2)
C.) (2z3, 5z7, z)
D.) no solution, inconsistent
I got D.
3. Solve using the method of your choice.
y2^x^2+2x=0
y=4^x+8
A) (4,2^24)
B) (4, 2^8)
C) (4, 2^24) (4, 2^8)
D) (4, 2^24) (4, 2^8)
I got B

Algebra Multiple Choice 
Knights
1. From substitution we get 42x= 5x2
So, 3x = 6, x=2, so y = 8: (2,8)
2. Should be D
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