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maths-probabilty(urgently needed)

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A box contains 5 red balls and 6 black balls. in how many ways can 6 balls be selected so that there are at least two balls of each color?

  • maths-probabilty(urgently needed) -

    please give answer

  • maths-probabilty(urgently needed) -

    i) 2 red,4 black => C(5,2)*C(6,4) =150
    ii)3 red,3 black => C(5,3)*C(6,3) =200
    iii)4red,2 black => C(5,4)*C(6,2) =75

    Therefore total number of ways =
    150+200+75 = 425 ways
    Hope this helps! Cheers! :)

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