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find the distance between M(1; 0; -3) point and 2x-2y+z+7=0 plane

  • Math -

    If (a,b,c) is any point, then its distance to
    Ax + By +Cz + D =0 is

    |Aa + Bb + Cc + D|/√(A^2 + B^2 + C^2)

    = |2(1) - 2(0) + 1(-3) + 7|/√(1 + 0 + 9)
    = 6/√10
    or
    = 6√10/10 = 3√10/5

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