How many moles of H2O would be produced if 3.61 molt HCI react with an excess of Ca(OH)2?
Do we balance equations anymore?
2HCl+ Ca(OH)2>> H2O + CaCl2
so it looks like you get one half the moles of HCl.
2HCl+ Ca(OH)2>> H2O + CaCl2
so it looks like you get one half the moles of HCl.