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Factor x^3 - 4x^2 + x + 6 with all steps

  • Math -

    let f(x) = x^3 - 4x^2 + x + 6
    f(1) = 1-4+1+6 ≠0
    f(-1) = -1 - 4 -1 + 6 = 0
    so (x+1) is a factor

    Using synthetic division or long algebraic division
    x^3 - 4x^2 + x + 6
    = (x+1)(x^2 - 5x + 6)
    = (x+1)(x-6)(x+1)

    so x = 6 or x = -1 (a double root at x=-1)

  • Math -

    thank you!

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