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posted by Labz Monday, June 4, 2012 at 5:54pm.

Factor x^3 - 4x^2 + x + 6 with all steps

let f(x) = x^3 - 4x^2 + x + 6 f(1) = 1-4+1+6 ≠0 f(-1) = -1 - 4 -1 + 6 = 0 so (x+1) is a factor Using synthetic division or long algebraic division x^3 - 4x^2 + x + 6 = (x+1)(x^2 - 5x + 6) = (x+1)(x-6)(x+1) so x = 6 or x = -1 (a double root at x=-1)

thank you!

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