math
posted by ALISSA .
Evaluate the following expressions for x=3
13)–2x^2 =
14)(2x)^2 =
10)Use the discriminant to determine
the number of solutions of 3x^24x+6=0
8)Solve sqrt[3b] = 3

13. 2*(3)^2 = 18.
14. (2x)^2 = (2*(3)^2 = 6^2 = 36.
10. 3x^2  4x + 6 = 0.
D = sqrt(B^24AC).
D = sqrt(1672) = sqrt(56).
The Discriminant is < 0; therefore, we
have no real solutions and 2 imaginary
solutions.
8. sqrt(3b) = 3
Square both sides:
3b = 9
b = 3,
CHECK: sqrt(3*3) = sqrt(9)=+3,AND 3.