The approximate pH of a 3.0 x 10-3 M solution of the strong acid H2SO4 is

a) 3.5
b) 3.0
c) 2.5

d) 2.2

e) -3.0
i got C by -log(3.0e-3) is this correct?

what is -log (2*.003)?

Sulfuric acid is diprotic.

The answer is d)

Yes, you are on the right track! The pH of a solution can be calculated using the formula: pH = -log[H+], where [H+] represents the concentration of the hydrogen ions in the solution.

In this case, you have a 3.0 x 10^-3 M (Molar) solution of the strong acid H2SO4. Since H2SO4 is a strong acid, it fully dissociates in water, producing two hydrogen ions (H+) for each molecule of H2SO4.

Therefore, the concentration of the hydrogen ions ([H+]) in the solution is 2 * 3.0 x 10^-3 M = 6.0 x 10^-3 M.

Now, you can plug this concentration value into the pH formula: pH = -log(6.0 x 10^-3).

By calculating this expression, you will find that the approximate pH of the solution is 2.22. Since the given options do not include this exact value, the closest option is d) 2.2.

So, your choice of option d) 2.2 is correct!