1) The approximate pH of a 3.0 X 10^-3 M solution of the strong acid H2SO4 is?
I did pH= -log(3.0 X 10^-3) = 2.5
2)If HCLO2 is a stronger acid than HF, which is stronger than HOCL, then the order of strengths of the conjugate bases of these acids is?
My answer is CLO2^-^ < F^-^ < CLO^-^ because the weaker the acid, the stronger its base. HOCL is the weakest acid so its base would be the strongest.
Would you agree with my answers? Thank you!
I think 2 is ok.
For #1, I agree this is an approximate number. Frankly, I don't know what an approximate pH is. It probably means ignoring k2 for H2SO4; if so then the 2.5 is fine.
Ok thank you!
1) Yes, your calculation is correct. To find the pH of a strong acid solution, you can use the formula pH = -log[H+], where [H+] represents the concentration of hydrogen ions in the solution. In this case, the concentration is 3.0 x 10^-3 M, so the pH is -log(3.0 x 10^-3) = 2.5.
2) Your reasoning is partially correct, but the order of strengths of the conjugate bases is not quite accurate. Remember that the conjugate base of a stronger acid is typically weaker than the conjugate base of a weaker acid. Based on the relative acid strengths given, the correct order of strengths for the conjugate bases is HOCl < HClO2 < HF.
So, the correct ordering would be CLO^- < CLO2^- < F^-. The conjugate base of the weakest acid, HOCl, would have the strongest basicity, and the conjugate base of the strongest acid, HF, would have the weakest basicity.