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6. A bowl contains 10 red balls, 10 green balls and 10 white balls. a. What is the probability of drawing 2 white balls with replacement? b. What is the probability of drawing 2 white balls without replacement?

  • math -

    when balls are replaced
    Prob(2white) = (10/30)(10/30) = 1/9

    without replacement
    prob(2white) = (10/30)(9/29) = 3/29

  • math -

    78

  • math -

    where is the fu*n solution

  • math -

    Probability of getting 2 white balls (W) with replacement is :
    P(W) = ( (10/30) * (10/30) ) = 1/9

    Probability of getting 2 white balls (W) without replacement is :
    P(W) = ( (10/30) * (9/29) ) = 3/29

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