math
posted by iris .
__X+1______x1____
x1 x+1

If that means
(x+1)/(x1)  (x1)/(x+1) then we have
[(x+1)^2  (x1)^2]/(x^21)
= [(x^2 + 2x + 1  (x^2  2x + 1)]/(x^21)
= 4x/(x^21)
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