Physics

posted by .

There are two particles (1 and 2) that are moving around in space. The force that particle 2 exerts on 1 is given by:

F21(t)=Fx*e^−(t/T)i^ + Fy*sin(2πt/T) j^

Where the parameters have the values:
Fx = 13.4 N
Fy = -84.2 N
T = 74 s
tf = 140.46 s

Find the average force from 1 on 2 from t = 0 until t = tf


Find the average force from 2 on 1 from t = 0 until t = tf

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics

    1)Three positive particles of charges 9µC are located at the corners of an equilateral triangle of side 15cm. Calculate the magnitude and direction of the force on each charge. 2)What is the electric field strength at a point in space …
  2. Physics

    A charged particle A exerts a force of 2.39 ìN to the right on charged particle B when the particles are 13.3 mm apart. Particle B moves straight away from A to make the distance between them 16.1 mm. What vector force does particle …
  3. PHYSICS

    a. A 25 nC particle and a – 7 nC particle is interacting with each other at a certain distance. Find the force between the two charges @ 3.0 cm and 1.0 cm Calculate and draw each of the particle’s electric fields. Calculate the …
  4. Precalculus

    Use one of the identities cos(t + 2πk) = cos t or sin(t + 2πk) = sin t to evaluate each expression. (Enter your answers in exact form.) (a) sin(19π/4) (b) sin(−19π/4) (c) cos(11π) (d) cos(53π/4) …
  5. calculus

    A particle moves on the x-axis so that its velocity at any time t is given by v(t) = sin 2t. At t = 0, the particle is at the origin. a)For 0 ≤ t ≤ π, find all values of t for which the particle is moving to the left. …
  6. physics

    Two forces, 1 = (3.85 − 2.85) N and 2 = (2.95 − 3.65) N, act on a particle of mass 2.10 kg that is initially at rest at coordinates (−2.30 m, −3.60 m). (a) What are the components of the particle's velocity …
  7. calculus

    F.(0) (10 puntos posibles) C1   What is limh→0cos(π6+h)−cos(π6)h?
  8. PHYSICS

    Chapter 07, Problem 48 Two particles are moving along the x axis. Particle 1 has a mass m1 and a velocity v1 = +5.0 m/s. Particle 2 has a mass m2 and a velocity v2 = -7.9 m/s. The velocity of the center of mass of these two particles …
  9. precalc

    Find the exact value of each expression, if it exists: the -1 are representing the inverse functions! (a) sin -1 (-√2/2) (b) cos−1 (−1) (c) sin( 􏰀sin−1 (π)􏰁) (d) cos−1􏰀(cos􏰀(−4π􏰁􏰁/ …
  10. physics

    Two particles are moving along the x axis. Particle 1 has a mass m1 and a velocity v1 = +4.3 m/s. Particle 2 has a mass m2 and a velocity v2 = -6.3 m/s. The velocity of the center of mass of these two particles is zero. In other words, …

More Similar Questions