calculus
posted by Brian .
Let M=1000. Which of the conditions is equivalent to f(x)= 1/((4x12)^2)>M?
a. absolute value of (x+3) is greater than or equal to .00158
b. absolute value of (x+3) is greater than or equal to .0553
c. absolute value of (x3) is less than .00791
d. absolute value of (x3) is less than .00158
e. absolute value of (x) is greater than .00395

We have
1/(4x12)^2 = 1/16(x3)^2 > 1000
(x3)^2 < 1/16000
x3 < 0.00791