physics

posted by .

An accelerating voltage of 2.46 * 10^3 V is applied to an electron gun, producing a beam of electrons originally traveling horizontally north in vacuum toward the center of a viewing screen 34.0 cm away.

What is the magnitude of the deflection on the screen caused by the Earth's gravitational field?


I am using this formula
v = squareroot(-2*q*V/m) to find speed and then B = mv/er for the magnitude

but they are asking the answer to be in meters...

  • physics -

    Well, I have a problem with the second equation. The deflection of the particle traveling in a magnetic field is based on force

    Force=m v B SinTheta where Theta is the angle between velocity and B.
    http://www.ux1.eiu.edu/~cfadd/1360/29MagFlds/HmwkSol.html

    But here, the velocity is North, which is almost parallel with the Earth's magnetic field, or zero force, and no deflection.
    Now in reality, The Earths magnetic field is not exactly North, and depending with latitude, not exactly parallel with Earth's axis. So it is somewhat complicated the exact angle between v and North Magnetic.
    I suspect you teacher wants you to assume zero force.

  • physics -

    sir i read through the site so when i use force 0 how should i solve this question?

    thank you

  • physics -

    see my answer posted elsewhere

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics - Help!

    A television set shoots out a beam of electrons. The beam current is 10E-6Amp (10macroAmp. How many electrons srike the TV screen each second?
  2. physics

    in an electron microscope, a tungstun cathode with work function 4.5 eV is heated to release electrons that are then initially at rest just outside the cathode. The electrons are accelerated by a potential difference to create a beam …
  3. physics

    The picture tube in an old black-and-white television uses magnetic deflection coils rather than electric deflection plates. Suppose an electron beam is accelerated through a 53.8-kV potential difference and then through a region of …
  4. physics

    An accelerating voltage of 2.46 * 10^3 V is applied to an electron gun, producing a beam of electrons originally traveling horizontally north in vacuum toward the center of a viewing screen 34.0 cm away. What is the magnitude of the …
  5. physics

    An accelerating voltage of 2.46 * 10^3 V is applied to an electron gun, producing a beam of electrons originally traveling horizontally north in vacuum toward the center of a viewing screen 34.0 cm away. What is the magnitude of the …
  6. physics

    An accelerating voltage of 2.46 * 10^3 V is applied to an electron gun, producing a beam of electrons originally traveling horizontally north in vacuum toward the center of a viewing screen 34.0 cm away. What is the magnitude of the …
  7. physics

    If an electron travels 0.250 m from an electron gun to a TV screen in 32.0 ns, what voltage was used to accelerate it?
  8. Physics

    If an electron travels 0.150 m from an electron gun to a TV screen in 19.0 ns, what voltage was used to accelerate it?
  9. physics

    If an electron travels 0.150 m from an electron gun to a TV screen in 19.0 ns, what voltage was used to accelerate it?
  10. Physics (Kinematics)

    In a television tube, the electron travels from an electron gun to the screen 0.45m away in 6.0×10exponent-9seconds. If the electron starts at rest, what is its final speed when it hots the screen?

More Similar Questions