chemistry

posted by .

A 375 g sample of well water is found to contain 17.0 mg of lead. How much lead (in parts per million) is in the well water? Round to the nearest tenth. Don't forget the unit.

  • chemistry -

    ok, lets go to millions...


    in 375million, there ware 17(milli x million) or 17,000 grams of lead.

    17,000/375,000,000 parts per million or

    17/375,000 or hhhhhmmmmmm. Round to the nearest tenth? so is it 45.3 ppm ?

  • chemistry -

    35.63

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. STATISTICS PLESE HELP!!

    studies indicate that drinking water supplied by some old lead-lined city piping systems may contain harmful levels of lead. an important study of the Boston water supply system showed that the distribution of lead content readings …
  2. statistics

    studies indicate that drinking water supplied by some old lead-lined city piping systems may contain harmful levels of lead. an important study of the Boston water supply system showed that the distribution of lead content readings …
  3. chemistry

    Lead pipes were once used to transport drinking water and are still found in some older homes and city water systems. Suppose the lead concentration and pH of the water determined by lead (II) hydroxide (Ksp = 2.8x10^-16) dissolving …
  4. chemistry

    A sample of water is found to contain 0.059 ppm of Pb2+ ions. Calculate the mass of lead ions per liter of this solution (assume the density of the water solution is 1.0 g/mL) 1.2E-2 g/L Pb2+ 5.9E-8 g/L Pb2+ 5.9E-5 g/L Pb2+ 1.2E-5 …
  5. chemistry

    A 375 g sample of well water is found to contain 17.0 mg of lead. How much lead (in parts per million) is in the well water?
  6. chemistry

    The acceptable limit for nitrate, often found in well water in agricultural areas, is 10 ppm. If a water sample is found to contain 355 µg/L, determine the concentration in parts per million, ppm. Express your answer in decimal form …
  7. algebra

    Lead shielding is used to contain radiation. The percentage of a certain radiation that can penetrate x millimeters of lead shielding is given by I(x) = 100e^−1.5x. What percentage of radiation, to the nearest tenth of a percent, …
  8. math

    Lead shielding is used to contain radiation. The percentage of a certain radiation that can penetrate x millimeters of lead shielding is given by I(x) = 100e^−1.5x. What percentage of radiation, to the nearest tenth of a percent, …
  9. algebra

    Lead shielding is used to contain radiation. The percentage of a certain radiation that can penetrate x millimeters of lead shielding is given by I(x) = 100e^−1.5x. What percentage of radiation, to the nearest tenth of a percent, …
  10. chemistry

    A 25.0 mL sample of drinking water suspected to contain lead(II) ions is treated with excess 0.800 M sodium chloride. A precipitate forms, which is filtered, dried, and weighed. 1.36 g of precipitate are collected. What was the concentration …

More Similar Questions