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Find the area enclosed by y = 1/x , y = 1/3x , x=3 and x=4

  • maths -

    y=f1(x)=1/x
    y2=1/3x

    area= int (1/x - 1/3x)dx from x=3 to 4

    area= lnx -1/3 lnx frm 3,4
    area= 2/3 (ln4-ln3)

    check my work

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