Here's a physics problem. I don't care about the answer, i just want to know how to do it. don't have to be too detailed.. but i don't really kno how to start this
1.) A model rocket blasts off from the ground rising straight upward with a constant acceleration that has a magnitude of 86 m/s^2 for 1.70 seconds, at which point fuel runs out. Air resistance neglected What maximum altitude will the rocket reach?
What I did: okay. so regarding number 1. I will use the first method. So I will calculate using this formula?
x = v0t + 1/2at^2,
in which case.. x = 86(1.70) + 1/2(-10)(1.70)^2? I get x, which would be the position.. how do figure out the height over initial velocity? do i plug 0 in for v0?
Where did you get Vo as 86?
where did you get acceleration as -10?
To determine the maximum altitude the rocket will reach, you will need to calculate the height at the time when the fuel runs out. Here's how you can approach the problem:
1. Start with the formula you mentioned: x = v0t + (1/2)at^2, where x is the displacement (height), v0 is the initial velocity, t is the time, and a is the acceleration.
2. You correctly identified the formula to use. However, in this case, since the rocket is moving upward, the initial velocity is not zero. It is given that the rocket has a constant acceleration of magnitude 86 m/s^2 for 1.70 seconds, so you need to consider the initial velocity as well.
3. To find the initial velocity, you can use another formula: v = v0 + at. Rearranging this formula, you get v0 = v - at. Since the rocket is starting from rest (initial velocity is zero), you can simply substitute v0 = -at.
4. Now, you have an expression for the initial velocity, which you can substitute back into the equation for displacement: x = (-at)t + (1/2)at^2.
5. Simplify the equation and solve for x. You can factor out t to get: x = -at^2/2 + at^2/2. The common term at^2/2 cancels out, and you are left with x = at^2/2.
6. Plug in the values given in the problem. The acceleration (a) is 86 m/s^2, and the time (t) when the fuel runs out is 1.70 seconds.
7. Substitute the values into the equation: x = (86 m/s^2)(1.70 s)^2/2.
8. Finally, calculate the value of x. This will give you the maximum altitude that the rocket will reach.
Remember to pay attention to the units of your final answer since the acceleration is in m/s^2 and time is in seconds, the resulting displacement will be in meters.
Once you complete these steps, you will have the maximum altitude the rocket will achieve.