A car travels 815 km in 10 days. at this rate, how far would it travel in 20 days?
What is 2 times 815?
Or -- you could set up a proportion:
815/10 = x/20
Cross multiply:
10x = 815*20
x = ?
815*20/10
=1630
To find the distance the car would travel in 20 days at the same rate, we can use a proportion.
Let's set up a proportion using the given information:
Distance / Time = Constant
Let's assign the variables:
Distance 1 = 815 km
Time 1 = 10 days
Distance 2 = unknown
Time 2 = 20 days
The proportion becomes:
815 km / 10 days = x km / 20 days
To solve for x, we can cross-multiply:
815 km * 20 days = 10 days * x km
Now, divide both sides of the equation by 10 to solve for x:
(815 km * 20 days) / 10 days = x km
Simplifying:
(16300 km * days) / 10 days = x km
Cancelling out the "days" units:
16300 km / 10 = x km
Calculating:
1630 km = x km
Therefore, the car would travel 1630 km in 20 days at the same rate.