Math
posted by Anonymous .
How do I solve 3log10of(x6)=11 and e^(2x)+10e^(x)25=0?

3log10of(x6)=11
log 10 (x6)^3 = 11
(x6)^3 = 10^11
x6 = 10^(11/3)
x = 10^(11/3) + 6
for the second, let e^x = a
then we have
a^2 + 10a  25 = 0
(a5)^2 = 0
a = + 5
e^x = 5 or e^x = 5 (the second has no solution)
x = ln5
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