math
posted by di .
15<3+2x less or equal to 89. Solve
as an intergal notation

15<3+2x<=89
subtract three
12<2x<=86
divide by 2
posted by di .
15<3+2x less or equal to 89. Solve
as an intergal notation
15<3+2x<=89
subtract three
12<2x<=86
divide by 2