posted by A. W. .
Here is what I got to do : write an inequality for my classmates to solve. In my inequality, use both the multiplication and addition properties of inequalities; before I summit this to class I want to know if I did it right: 5(x + 8) -6 > 4(x + 6);
5x + 40 - 6 > 4x + 24; 5x + 44 - 44 > 4x + 24 - 44; 5x - 4x > 4x - 4x -20; 1x/1 < -20/1; x<-20, is this right?
5(x + 8) -6 > 4(x + 6);
5x + 40 - 6 > 4x + 24;
5x + 44 - 44 > 4x + 24 - 44;
5x - 4x > 4x - 4x -20;
1x/1 < -20/1; Where in the world did you get this step? You did not divide by a negative.
I got 5x-4x> 4x - 4x-20; 1x< -20; you have to get x by itself so you divide both side by 1; 1x/1 < -20/1; x< -20 that is how I got x<-20
I agree with your 5x-4x> 4x - 4x-20;
that simplifies to x>-20
From there, your work makes no sense, and is in fact wrong. Dividing by 1 does not reverse the inequality sign