Statistics
posted by JMN .
John has six bills of paper money in the following denominations $1, $5, $10, $20, $50, and $100. If he selects 3 bills at a time what is the probability of selecting a group that has an average value of at least $26?

Statistics 
bobpursley
I would figure the prob of getting 25 or less first.
You cant choose three of those bill to get 25 or less. So the probablility of getting an average of 26 dollars is 1.
Now, if you mean by average value getting a total amount on the three bills of 26*3 or more,
Pr(78dollars)=Pr(100, x x)=1/6
pr(50,20, x)=1/6*1/5
Pr(50,10,10)=1/6*1/5*1/4
I don't see any other way to get a total of 78 dollars or more, so add these three probablilities. 
Statistics 
Anonymous
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